Question

Question 6

20 pts
The vertices of a triangle are (3,-2), (5,-8) and (-2, 1). What is the approximate perimeter of the
triangle
O 17
O 33
O 24
042

Answer 1

24

Step-by-step explanation:

You have to find the distance between two points three times

D =
`\sqrt{(x_(1)-x_(2))^2 + (y_(1) - y_(2))^2`

1. Distance between (3,-2) (5, -8) =
`√((3 - 5)^2+ [-2 - (-8)]^2)` =
`√((-2)^2 + (6)^2)`

=
`√(4 + 36)` =
`√(40)`

2. Distance between (5, -8) (-2, 1)
`√([5 - (-2)]^2 + (-8- 1)^2 )` =
`√((7)^2 + (-9)^2 )`

=
`√(49 + 81)` =
`√(130)`

3. Distance between (-2, 1)(3, -2) =
`√((-2 - 3)^ + [1 -(-2)]^2)` =
`√((-5)^2 + (3)^2)`

=
`√(25 + 9)` =
`√(34)`

Perimeter = distance 1 + distance 2 + distance 3

=
`√(40)` +
`√(130)` +
`√(34)`

= 6.32 + 11.40 + 5.83

= 23.55 ≈ 24