Question

What are the answers to all of these

Answer 1

Answer/Step-by-step explanation:

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`(1)/(3)*(2)/(4)`

`\mathrm{Cancel\:the\:numbers:}\:(2)/(4)=(1)/(2)`

`=(1)/(3)\cdot (1)/(2)`

`\mathrm{Apply\:the\:fraction\:rule}:\quad (a)/(b)\cdot (c)/(d)=(a\:\cdot \:c)/(b\:\cdot \:d)`

`=(1\cdot \:1)/(3\cdot \:2)`

`\mathrm{Multiply\:the\:numbers:}\:1\cdot \:1=1`

`=(1)/(3\cdot \:2)`

`\mathrm{Multiply\:the\:numbers:}\:3\cdot \:2=6`

`=(1)/(6)`

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`(1)/(6)*(4)/(9)`

`\mathrm{Apply\:the\:fraction\:rule}:\quad (a)/(b)\cdot (c)/(d)=(a\:\cdot \:c)/(b\:\cdot \:d)`

`=(1\cdot \:4)/(6\cdot \:9)`

`\mathrm{Multiply\:the\:numbers:}\:1\cdot \:4=4`

`=(4)/(6\cdot \:9)`

`\mathrm{Factor\:the\:number:\:}\:4=2\cdot \:2`

`=(2\cdot \:2)/(6\cdot \:9)`

`\mathrm{Factor\:the\:number:\:}\:6=2\cdot \:3`

`=(2\cdot \:2)/(2\cdot \:3\cdot \:9)`

`\mathrm{Cancel\:the\:common\:factor:}\:2`

`=(2)/(3\cdot \:9)`

`\mathrm{Multiply\:the\:numbers:}\:3\cdot \:9=27`

`=(2)/(27)`

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`(2)/(3)*(7)/(8)`

`\mathrm{Apply\:the\:fraction\:rule}:\quad (a)/(b)\cdot (c)/(d)=(a\:\cdot \:c)/(b\:\cdot \:d)`

`=(2\cdot \:7)/(3\cdot \:8)`

`\mathrm{Factor\:the\:number:\:}\:8=2\cdot \:4`

`=(2\cdot \:7)/(3\cdot \:2\cdot \:4)`

`\mathrm{Cancel\:the\:common\:factor:}\:2`

`=(7)/(3\cdot \:4)`

`\mathrm{Multiply\:the\:numbers:}\:3\cdot \:4=12`

`=(7)/(12)`

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`\frac{2}4*(2)/(5)`

`\mathrm{Cancel\:the\:numbers:}\:(2)/(4)=(1)/(2)`

`=(1)/(2)\cdot (2)/(5)`

`\mathrm{Cross-cancel\:common\:factor:}\:2`

`=\frac{1}5`

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Code: 6 2 12 1

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