Question

The parabola has y intercept of -2 and turning point at (2,2)

Give the equation of this parabola?​

Answer 1

y=-(x-2)^2+2

Explanation:

The equation for a parabola is y= a(x-h)^2+k.

The turning point is (2,2) which represents the (h,k) value

y=a(x-2)^2+2

Now solve for a. by using the y-int is (0,-2), and plugging it into the equation.

-2=a(0-2)^2+2

a= -1

Plug your a value into the equation.

y=-(x-2)^2+2