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Explain the error in Julie’s work in rewriting the radical expression.

Explain the error in Julie’s work in rewriting the radical expression.-example-1

2 Answers

6 votes

Answer:

The negative numbers do not have square roots. Therefore the question does not have a solution. That is where Julie made a mistake.

Explanation:

User Aleksandr Blekh
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7.7k points
4 votes

Answer:

-6

Explanation:

First, let's take a look at this property:


\displaystyle \large{ √(a) √(b) = √(ab) }

This only works for a and b ≥ 0.

As for a & b < 0 which results in Imaginary Number, we have to convert in 'i' form.

We know that:-


\displaystyle \large{ i = √( - 1) }

Thus:


\displaystyle \large{ √( - 3) \cdot √( - 12) = √(3) i \cdot √(12)i }

Then we can multiply 12 & 3 in square root.


\displaystyle \large{ √( - 3) \cdot √( - 12) = √(36) {i}^(2) }

We know that:


\displaystyle \large{ {i}^(2) = - 1}

Convert i^2 to -1


\displaystyle \large{ √( - 3) \cdot √( - 12) = √(36)( - 1) } \\ \displaystyle \large{ √( - 3) \cdot √( - 12) = - √(36)}

Then evaluate √36 which is 6.


\displaystyle \large{ √( - 3) \cdot √( - 12) = - 6}

Therefore the answer should be -6.

Conclusion

Julie cannot use the √a√b = √ab property first because a & b both are < 0 and the property applies for a ≥ 0, b ≥ 0.

User Joshua H
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6.9k points