Answer:
|x+2| > 3
Explanation:
We know that if |x| > a then (-a > x) ∨ (x > a).
(x+5 > 6) ∨ (x+5 < 0) ⇒ (0 > x+5) ∨ (x+5 > 6) |-3 ⇒
⇒ (-3 > x+2) ∨ (x+2 > 3) ⇒ |x+2| > 3
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