Question

1. What amount of ammonia (in moles) is produced by the reaction of 4.00 mol H2 with 3.00 mol Nz?

3 H2(g) + N2(g) → 2 NH3(g)

Answer 1

Answer: 6 moles

Step-by-step explanation:

3 H₂ + N₂ → 2 NH₃

↓ ↓

4 mol 3 mol

Since the moles of N₂ is the smaller of the two reactants, then N₂ is the limiting factor (the reactant that will decide how much ammonia is produced since it has the smaller amount of moles). ∴ we have to use it in calculating the number of moles of ammonia

The mole ratio of N₂ to NH₃ based on the balanced equation is 1 to 2.

∴ the moles of NH₃ = moles of N₂ × 2

= 3 moles × 2

= 6 moles