Question

Calcium carbonate decomposes into calcium oxide and carbon dioxide when heated. Calculate the mass of carbon dioxide released when 300 g of calcium carbonate is heated.

Answer 1

Upon heating 300 g of calcium carbonate (CaCO₃), 132 g of carbon dioxide (CO₂) will be released according to the stoichiometry of the reaction. The result confirms the law of conservation of mass.

Step-by-step explanation:

To calculate the mass of carbon dioxide (CO₂) released when 300 g of calcium carbonate (CaCO₃) is heated, we can use stoichiometry based on the decomposition reaction of CaCO₃. From the examples provided, we can see that heating 10.0 grams of CaCO₃ produces 4.4 g of CO₂. This is a stoichiometry ratio that we can use to determine the amount of CO₂ produced from 300 g of CaCO₃.

The stoichiometry of the reaction is such that 10 g of CaCO₃ produces 4.4 g of CO₂. So, we can set up a proportion to solve for the mass of CO₂ produced from 300 g:

• 10 g CaCO₃ : 4.4 g CO₂ = 300 g CaCO₃ : x g CO₂

By cross-multiplying, we get:

• x g CO₂ = (300 g CaCO₃ × 4.4 g CO₂) / 10 g CaCO₃

x g CO₂ = 132 g CO₂

Therefore, upon heating 300 g of CaCO₃, 132 g of CO₂ will be released.

The above calculation confirms the law of conservation of mass, which states that mass cannot be created or destroyed in a chemical reaction. The total mass of the reactants equals the total mass of the products.

Answer 2

Answer: 131.9 g

Step-by-step explanation:

Write a Balanced Equation for the decomposition

CaCO₃ → CaO + CO₂

Find Moles of CO₂ Produced

Since the mole ratio of CaCO₃ to CO₂ is 1 to 1,

the moles of CaCO₃ = moles of CO₂

moles of CaCO₃ = mass ÷ molar mass

= 300 g ÷ 100.087 g/mol

= 2.997 moles

∴ moles of CO₂ = 2.997 moles

Determine Mass of CO₂

Mass = moles × molar mass

= 2.997 mol × 44.01 g/mol

= 131.9 g

∴ when 300 g of calcium carbonate is decomposed, it produces 131.9 g of carbon dioxide.