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Write the equation of the line passing through the points (15,4) and (-3,-3) please helppp 10 points pleaseeeeeeeeeee

Write the equation of the line passing through the points (15,4) and (-3,-3) please-example-1
User Kidquick
by
8.4k points

2 Answers

6 votes

Answer:
y = (1)/(3)x-2

This is the same as writing y = (1/3)x - 2

Slope = 1/3

y intercept = -2

======================================================

Step-by-step explanation:

We first need to determine the slope


m = (y_2-y_1)/(x_2-x_1)\\\\m = (-3-3)/(-3-15)\\\\m = (-6)/(-18)\\\\m = (1)/(3)\\\\

Then we'll use this value of m, along with (x,y) = (15,3), to determine the y intercept b value.


y = mx+b\\\\3 = (1/3)(15)+b\\\\3 = 5+b\\\\3 - 5 = b\\\\-2 = b\\\\b = -2

You could use the other point (-3,-3) as well


y = mx+b\\\\-3 = (1/3)(-3)+b\\\\-3 = -1+b\\\\-3 +1 = b\\\\-2 = b\\\\b = -2

Either way, we end up with the same y intercept. You don't need to show both sets of steps when computing b. You only need to pick one set of steps.

Since m = 1/3 and b = -2, we go from y = mx+b to y = (1/3)x - 2 which is the same as writing
y = (1)/(3)x-2

User Vlad Dogaru
by
8.3k points
5 votes

Answer:

y = 7/18 - 11/6

Step-by-step explanation:

y2 - y1 / x2 - x1

-3 - 4 / -3 - 15

-7/-18

= 7/18

y = 7/18x + b

4 = 7/18(15) + b

4 = 35/6 + b

-11/6 = b

User Reevesy
by
8.4k points

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