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5 votes
How to make h the subject in
m= r - h + 4d

2 Answers

7 votes

Answer:

h = 4d -m + r

Explanation:

m = r-h +4d

h = 4d -m + r

we know when the real root is r = h-4d

the m+h = r+4d is step 1

then simply h-m = 4d-m + r is step 2

then h = 4d -m + r

User Dostee
by
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6 votes

9514 1404 393

Answer:

h = r +4d -m

Explanation:

There are a couple of ways to go about this:

1) Solve it the way you would any 2-step linear equation.

Step 1:

Identify the terms that do not involve h on the side of the equation that has the h-term. Subtract those terms from both sides of the equation.

m -r -4d = -h

Step 2:

If the coefficient of h is not 1, divide both sides of the equation by that coefficient.

(m -r -4d)/(-1) = (-h)/(-1)

-m +r +4d = h

I like to have the leading coefficient be positive, so I might write this as ...

h = 4d +r -m

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2) The only h term has a -1 coefficient, so it can be given a coefficient of +1 by adding h to both sides of the equation.

h +m = r +4d

There is an unwanted m term with the h term, so subtract that from both sides of the equation.

h = r +4d -m

User Bill Melius
by
8.2k points

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