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You throw a ball upward with an initial speed of 3.0 m/s from an initial height of 1.5 m. After you throw the ball, its acceleration is 9.81 m/s downward. Taking upward to be the positive direction, write the position-time equation for the ball's motion​

User Kodeaben
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Answer:

vf^2=vo^2+2ay(y1-y0)

Step-by-step explanation:

User Vicolored
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Answer: An object undergoing a constant acceleration can have its motions be described by the kinematic equations. These equations relate the position of the particle, its velocity, acceleration, and time.

Step-by-step explanation:

User Keammoort
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