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Give the slope perpendicular to the equation 2x-y=5

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Answer:

-
(1)/(2)

Explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Given

2x - y = 5 ( subtract 2x from both sides )

- y = - 2x + 5 ( multiply through by - 1 )

y = 2x - 5 ← in slope- intercept form

with slope m = 2

Given a line with slope m then the slope of a line perpendicular to it is


m_(perpendicular) = -
(1)/(m) = -
(1)/(2)

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