Question

How much heat is absorbed by 0.050kg of lead when it is heated from 20°C to 100°C?

Answer 1

Mass of substance m = 0.050Kg

Initial Temperature T₁ = 20°C

Final Temperature T₂ = 100°C

we have to calculate the heat absórbed by the lead .

Since spècific heat of lead is not gíven so we will take spècific heat of lead 128 J/kg°C

`\diamond \bf \: Q\: = m * c( \Delta \: t)`Put the given value

`\sf \longrightarrow \: Q = 0.050 * 128 * (100 - 20) \\ \\ \\ \sf \longrightarrow \: Q = 0.050 * 128 * (80) \\ \\ \\ \sf \longrightarrow \: Q = 6.4 * 80 \\ \\ \\ \sf \longrightarrow \: Q = 512 \: joules`

Therefore,

• Heat absórbed by the lead is 512 Joules.