Answer:
2x+8/x^2-x-6
Explanation:
=x^2+4x-1x-4
=(x-1)(x+4)
=x^2+2x+2x+4
=(x+2)(x+2)
=x^2-3x-1x+3
=(x-1)(x-3)
= (x-1)(x+4)/(x+2)(x+2) x 2x (x+2)/(x-1)(x-3)
= (x+4)(2)/(x+2)(x-3)
= 2x+8/x^2-x-6
Restrictions:
x cannot = -2, 1, 3,
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