1 Answer

Charter · Answer 1 · 2022-06-28T09:41:39+0000

Answer:

$\huge\boxed{\sf Q = 5880\ Joules}$

Step-by-step explanation:

Given:

m = mass = 40 g = 0.04 kg

c = specific heat constant of water = 4200 J/Kg°C

ΔT = change in temperature = T2-T1 = 60 °C - 25 °C = 35°C

Required:

Q = change in heat energy = ?

Formula:

Q = mcΔT

Solution:

Q = (0.04)(4200)(35)

Q = 5880 Joules

$\rule[225]{225}{2}$

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