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When the speed of a moving car is doubled, how much more kinetic energy does it have?

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Answer: 4 times

Step-by-step explanation:

KE1 = (1/2)mv^2

KE2 = (1/2)m(2v)^2 or (1/2)m*4v^2

KE2/KE1 = ((1/2)m*4v^2)/((1/2)mv^2) = 4 times

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