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Write an equation of the line that passes through the point (6,2) and is perpendicular to the line y=3x+3

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Answer:

y = -
(1)/(3)x + 4

Explanation:

To find the slope of a perpendicular line, find the negative reciprocal of the slope.

The slope is 3 so the slope of the perpendicular line would be -
(1)/(3)

________________

Then use point slope form to find the equation of the perpendicular line:

y -
y_(1) = m (x -
x_(1) )

point = (6, 2)

slope = -
(1)/(3)

y - 2 = -
(1)/(3) (x - 6)

________________

If you want it in slope intercept form, you can just rearrange the equation:

y = 2 -
(1)/(3)x +2

y = -
(1)/(3)x + 4

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