Question

A ball Of Mass. 0.5 kg initially at rest is kick directly toward offense from appoint 20 m away as shown below the velocity of the ball as it leaves the kickers foot is 16 M/S at angle 45 degrees above the horizontal the top of the fence is 4 m high the ball hits nothing Wallen flight and a resistance is negligible the acceleration due to gravity is 9.8 M/S^2 determine the time it takes for the ball to reach the plane of the fence.

Answer 1

a. The horizontal component of the velocity is constant so vxt = d where vx = v0 cosθ = 16m/s t = d/v = 2s

b. The height of the ball during its flight is given by y = v0yt + ½ gt2 where v0y = v0sinθ = 12m/s and g = –9.8m/s2 which gives at t = 2s, y = 4.4m. The fence is 2.5m high so the ball passes above the fence by 4.4m – 2.5m = 1.9m

Step-by-step explanation: