Ten times the smallest of three consecutive integers is 213 more than the sum of the other two integers. Find the integers.

asked Dec 24, 2022 216k views

5 votes

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7 votes

Answer:

27,28 and 29

Explanation:

10*a = a+1+a+2+213

10a - 2a = 216

8a = 216

a = 27

27, 28, and 29

ThangLeQuoc answered Dec 30, 2022

3.3k points

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