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2 log x - log y - 2 log z as a single logarithm

User BahmanM
by
8.0k points

2 Answers

3 votes

Answer:


log(x^2)/(yz^2)

Explanation:

Simplify 2log(x) by moving 2

inside the logarithm.

Simplify 2log(x) by moving 2

inside the logarithm.

log(x^2)−log(y)−2log(z)

Simplify −2log(z)

by moving 2

inside the logarithm.

log(x^2)−log(y)−log(z^2)

Use the quotient property of logarithms, logb (x)−logb (y)=logb (x/y)


log(x^2)/(y) - log(z^2)

Use the quotient property of logarithms, logb(x)−logb(y)=logb (x/y)


log ((x)/(y))/( (1)/(z^2)}]

Multiply the numerator by the reciprocal of the denominator.


log(x^2\\ )/(y).(1)/(z^2)

Combine.


log(x^2*1\\ )/(yz^2)

Multiply
x^(2) by 1


log(x^2)/(yz^2)

User Guerdy
by
8.9k points
5 votes

Answer:

log ( x^2/(yz^2))

Explanation:

2 log x - log y - 2 log z

We know a log b = log b^a

Rewriting

2 log x = log x^2 and 2 log z = log z^2

log x^2 - log y - log z^2

Rewriting

log x^2 - (log y + log z^2)

We know that log a + log b = log (a*b)

log x^2 - (log (y z^2))

And we know log a - log b = log (a/b)

log ( x^2/(yz^2))

User Hop
by
7.5k points

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