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Foundation Geometry midpoint of AC A. 18 B. 6 C.27 D.54
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Foundation Geometry
midpoint of AC

A. 18
B. 6
C.27
D.54

Foundation Geometry midpoint of AC A. 18 B. 6 C.27 D.54-example-1
User Mddw
by
5.3k points

1 Answer

6 votes

Answer:

D

Explanation:

Since B is the midpoint of AC , then

AB = BC , substitute values

4x + 3 = 3x + 9 ( subtract 3x from both sides )

x + 3 = 9 ( subtract 3 from both sides )

x = 6

Then

AC = AB + BC

= 4x + 3 + 3x + 9

= 7x + 12

= 7(6) + 12

= 42 + 12

= 54 → D

User Rajkumar R
by
5.3k points
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