Question

Please assist, no links

Answer 1

`(1)/(a^(7) )`

Explanation:

Use this rule:

`(x^a)/(x^b)=x^(a-b)`

So, this gives you

`a^(-13+6)`

This equates to:

`a^(-7)`

However, we cant leave the exponent negative, so we use this formula:

`a^(-b)=(1)/(a^b)`

So, the answer is:

`(1)/(a^(7) )`

Answer 2

There is no denominator a^-7

The power is positive 1/a^7

Explanation:

Remark

We are not told what the restrictions on the power are. Here are the possibilities.

• There is no denominator.
• The power must be positive.

So I will give the answer to both conditions. You will have to choose.

There is no denominator

That means that The powers are subtracted

Multiply numerator and denominator by a+6

a^- 13 * a^6

=========

a^-6 * a^6

To start a^(-6 + 6) = a^0 which = 1. That is not written, so you are left with a^ (-13 + 6) = a ^ -7

The answer must have a positive power.

Multiply the numerator and denominator by a^13.

numerator

a^-13 * a^13

a^(-13 + 13)

a^0

1

So we are left with 1 in the numerator.

a^-6 * a^13

a^(-6 + 13)

a^7

Answer: what is left is 1/a^7