Question

A line with the slope of -3 passes through (-8, p) and (2, 3p). Find the value of p

Answer 1

To find the Slope: Slope Formula: m = y2 −y1 x2 −x1. Given points: P (6,2) and S(3,1) will be our (x1,y1) and (x2,y2) respectively. Hence x1 = 6,y1 = 2,x2 = 3,y2 = 1. Slope(m) = 1 −2 3 −6. ⇒ −1 −3 = 1 3.

Explanation:

Answer 2

p = -15

Explanation:

`-3=(3p-p)/(2-(-8)) =(2p)/(10)`

`(2p)/(10) =-3`

`2p=-3(10)`

`p=(-30)/(2)`

`p=-15`

`m=(-45-(-15))/(2-(-8)) =(-45+15)/(2+8) =(-30)/(10) =-3`

I hope this help you