Question

A training field is formed by joining a rectangle and two semicircles, as shown below. The rectangle is 100 m long and 60 m wide.

Find the area of the training field. Use the value 3.14 for , and do not round your answer. Be sure to include the correct unit in your answer.

Answer 1

8826 m²

Explanation:

The field is composed of a rectangle and a circle .( the 2 semicircles form a complete circle when placed together )

area = area of rectangle + area of circle

= lb + πr² ( r = 60 ÷ 2 = 30 )

= (100 × 60) + (3.14 × 30²)

= 6000 + (3.14 × 900)

= 6000 + 2826

= 8826 m²

Answer 2

Explanation:

given,

length = 100 m

breadth = 60 m

we know,

area = l × b

now,

100 × 60 = 6000 m

therefore, area of rectangular field is 6,000 m.

and for both the semicircle if we add both the semicircle we will get a complete circle.

as the width of the rectangle is the diameter of circle so the radius of the circle is 60/2 = 30m

we know,

Area = πr²

now,

→ 3.14 × 30²

→ 3.14 × 900

→ 2826 m

so,

area of rectangle + area of circle = area of the training field.

→ 6000 + 2826 = 8826.

therefore, area of training field is 8,826 m.

hope this answer helps you dear...take care and may u have a great day ahead!