Question

Help me plzzz

The punter on a football team tries to kick a football so that it stays in the air for a long "hang
time". If the ball is kicked with an initial velocity of 30 m/s at an angle of 60 degrees above the
ground.

a. Calculate the "hang time".

b. How far does the ball go in the horizontal direction?

c. What is the maximum altitude (height) the ball reaches?

Answer 1

first resolve the initial velocity of the ball into two components

1)one parallel to ground(u)

2)another perpendicular to ground(v)

call the initial velocity=p=25.4 m/s at 58.0° deg to ground

so the horizontal component of velocity=25.4cos58=13.46 m/s

so the vertical component of velocity=25.4sin58=21.54 m/s

we have nothing to do with the horizontal component of velocity as it plays no part in the hang time

only vertical component of velocity determines the hang time

hang time=2*(vertical component of velocity)/(acceleration due to gravity)

==>hang time=2*21.54/9.8=4.39 s

==>hang time =4.39 s

If I'm wrong please let me know, thank you.