Question

During a hot summer week, Mr. Singh sold 60 watermelons. On Monday, he sold

he sold half the number of watermelons he sold on Monday. On Thursday, Mr. Singh sold 18
watermelons. On Tuesday, he sold twice as many watermelons than Monday. On Wednesday,
watermelons. On Friday, he sold four more than twice the amount he sold on Monday and
Tuesday combined. How many watermelons did he sell on Friday?


Help please

Answer 1

Mr. Singh sold 184 watermelons on Friday.

Step-by-step explanation:

To find out how many watermelons Mr. Singh sold on Friday, we need to calculate the number of watermelons he sold on Monday, Tuesday, and the combined number of watermelons he sold on Monday and Tuesday.

Let's start by calculating the number of watermelons he sold on Monday. According to the information given, he sold half the number of watermelons he sold on Monday. Therefore, if he sold 60 watermelons in total, he sold 60/2 = 30 watermelons on Monday.

Next, we need to find out the number of watermelons he sold on Tuesday. According to the information given, he sold twice as many watermelons as Monday. Therefore, if he sold 30 watermelons on Monday, he sold 2 * 30 = 60 watermelons on Tuesday.

Now, let's calculate the combined number of watermelons he sold on Monday and Tuesday. The total number of watermelons sold on Monday and Tuesday is 30 (Monday) + 60 (Tuesday) = 90.

Finally, to find out how many watermelons Mr. Singh sold on Friday, he sold four more than twice the amount he sold on Monday and Tuesday combined. Therefore, the number of watermelons he sold on Friday is 2 * 90 (Monday and Tuesday) + 4 = 180 + 4 = 184 watermelons.

Answer 2

what's half 60? 30. hope that helps!