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4 votes
Based on the information in the table, what

is the acceleration of this object?
(m/s)
t(s)
0.0
3.0
1.0
1.0
2.0
-1.0
3.0
-3.0
A. -3.0 m/s2
B. 2.0 m/s2
C. 1.0 m/s2
D. -2.0 m/s2

Based on the information in the table, what is the acceleration of this object? (m-example-1
User Ericb
by
7.9k points

1 Answer

5 votes

Answer:

-2.0 m/s^2

Explanation:

Acceleration can be found by:


\displaystyle \large{ (dv)/(dt) = a }

where a = acceleration.

or


\displaystyle \large{ (v_2 - v_1)/(t_2 - t_1) = a }

Using two values or points.

t1 = 0 and v1 = 3

t2 = 1 and v2 = 1

Substitute in:


\displaystyle \large{ (1-3)/(1-0) = a } \\ \displaystyle \large{ ( - 2)/( 1) = a } \\ \displaystyle \large{-2 = a }

Therefore acceleration is -2.0 m/s^2

User Vyakhir
by
8.4k points

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