Question

A bicycle takes 8.0 seconds to accelerate at a constant rate from rest to a speed of 4.0 m/s. If the mass of the bicycle and rider together is 85 kg, what is the net force acting on the bicycle? (Hint: first, calculate acceleration) Acceleration = Fnet =​

Answer 1

`\sf\longmapsto42.5 N`

Step-by-step explanation:

We would need to use Newton's second law ofmotion, which states that-

`\sf \longmapsto \: F _(net) = m•a`

We know that,

`\sf \longmapsto \: a = (v - u)/(t)`

Here,v = 4 m/s, u = 0 m/s, t = 8 s

`\sf \longmapsto \: a = (4 \: m/s - 0 \: m/s)/(8s) = 0.5 \: m / {s}^(2)`

Also, we have

m = 85 kg

`\sf \longmapsto \: F _(net) = 85 \: kg \: • \: 0.5 m / {s}^(2) \: \: = 42.5 \: N`

Answer 2

42.5km/s^2

Step-by-step explanation:

Fnet=m⋅a

We know that

`a=(v-u)/(t)`

Here,

v=4m/s, u=0m/s, t=8s

`a=(4m/s-0m/s)/(8s) =0/5m/s^2`

Also, we have m=85kg

Fnet=85 kg⋅0.5 m/s2=42.5N

Acceleration = (change in speed) / (time for the change)

Acceleration = (4 m/s) / (8 seconds)

Acceleration = 0.5 m/s²

Force = (mass) x (acceleration)

Force = (85 kg) x (0.5 m/s²)

Force = 42.5 Newtons