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What is the net force on a cart being pushed with an applied force of 23 N with a frictional force of 23 N? I​

2 Answers

5 votes

Answer:

1N

Step-by-step explanation:

Pretty simple Divide 23 by 23 which gives you 1.

23N ÷ 23N = 1N

User Chirality
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3.1k points
4 votes

Answer:


\sf \longmapsto \: 1 \: N

Step-by-step explanation:


\sf \longmapsto (23N)/(23N)


\sf \longmapsto1 \: N

User Vsz
by
3.5k points