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If a+b=26 what is the value of 2(a+b)+ a+b/6+(a+b)^2-2​

User Scottru
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1 Answer

2 votes

Answer:

730 1/3

Explanation:

It should be written as:

2(a+b)+ (a+b)/6+(a+b)^2-2, so that the quantity a + b is divided by 6 and not just b.

Hence, we have that

​2(a+b)+ (a+b)/6+(a+b)^2-2 =

2(26) + 26/6 + 26^2 - 2 =

52 + 13/3 + 676 - 2 =

52 + 4 1/3 + 674 =

1/3 + 56 + 674 =

1/3 + 730 =

750 1/3

User Beckettsean
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