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If a + b = 10 what is the value of 2(a + b) + a + b/6 + (a + b) ^ 2 - 2

If a + b = 10 what is the value of 2(a + b) + a + b/6 + (a + b) ^ 2 - 2-example-1
User Gravitoid
by
7.5k points

2 Answers

4 votes

Answer:


(359)/(3) or
119~(2)/(3)

Explanation:

Let
x=a+b. Then, the expression just reduces to
2x+(x)/(6)+x^2-2.

But we know that
a+b=x=10!

Plugging in for
x gives
2(10)+(10)/(6)+10^2-2=20+(5)/(3)+100-2=118+(5)/(3)=(359)/(3).

So, the answer is
\boxed{(359)/(3)} and we're done!

User BenVlodgi
by
8.1k points
6 votes

Answer:


{ \rm{2(a + b) + (a + b)/(6) + {(a + b)}^(2) - 2}} \\

• substitute (a + b) with 10:


= { \tt{2(10) + (10)/(6) + {(10)}^(2) - 2 }} \\ \\ = { \tt{20 + (10)/(6) + 100 - 2}} \\ \\ { \boxed{ \tt{ = 119 (2)/(3) }}}

User Commander
by
7.9k points

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