Answer:
4mfro• (2m2+10m+1)•(2m2+2m-3)
STEP
1
:
Equation at the end of step 1
0-((((((((2•(m2))+10m)+1)•f)•r)•o)•m)•(((0-23m2)-8m)+12))
STEP
2
:
Equation at the end of step
2
:
0-(((((((2m2+10m)+1)•f)•r)•o)•m)•(-8m2-8m+12))
STEP
3
:
Trying to factor by splitting the middle term
3.1 Factoring 2m2+10m+1
The first term is, 2m2 its coefficient is 2 .
The middle term is, +10m its coefficient is 10 .
The last term, "the constant", is +1
Step-1 : Multiply the coefficient of the first term by the constant 2 • 1 = 2
Step-2 : Find two factors of 2 whose sum equals the coefficient of the middle term, which is 10 .
-2 + -1 = -3
-1 + -2 = -3
1 + 2 = 3
2 + 1 = 3
Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factored
Equation at the end of step
3
:
0-((((f•(2m2+10m+1)•r)•o)•m)•(-8m2-8m+12))
STEP
4
:
Equation at the end of step 4
0-(((fr•(2m2+10m+1)•o)•m)•(-8m2-8m+12))
STEP
5
:
Equation at the end of step 5
0-((fro•(2m2+10m+1)•m)•(-8m2-8m+12))
STEP
6
:
Equation at the end of step 6
0 - (mfro • (2m2 + 10m + 1) • (-8m2 - 8m + 12))
STEP
7
:
STEP
8
:
Pulling out like terms
8.1 Pull out like factors :
-8m2 - 8m + 12 = -4 • (2m2 + 2m - 3)
Trying to factor by splitting the middle term
8.2 Factoring 2m2 + 2m - 3
The first term is, 2m2 its coefficient is 2 .
The middle term is, +2m its coefficient is 2 .
The last term, "the constant", is -3
Step-1 : Multiply the coefficient of the first term by the constant 2 • -3 = -6
Step-2 : Find two factors of -6 whose sum equals the coefficient of the middle term, which is 2 .
-6 + 1 = -5
-3 + 2 = -1
-2 + 3 = 1
-1 + 6 = 5
Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factored
Equation at the end of step
8
:
0 - -4mfro • (2m2 + 10m + 1) • (2m2 + 2m - 3)
STEP
9
:
Final result :
4mfro • (2m2 + 10m + 1) • (2m2 + 2m - 3)