Question

an unknow charge is placed in an electric field of intensity 54 N/c and experiences aforce due to its electri nature 3.7×10 -2 calculate the value of the carge​

Answer 1

The value of the charge can be found using the equation q = F/E, where q is the charge, F is the electric force, and E is the electric field strength.

Step-by-step explanation:

The electric force on a charge in an electric field is given by the equation F = qE, where F is the force, q is the charge, and E is the electric field strength. In this case, the electric force is 3.7×10-2 N and the electric field intensity is 54 N/C. To find the value of the charge, we can rearrange the formula as q = F/E.

Substituting the given values, we have q = 3.7×10-2 N / 54 N/C = 6.85×10-4 C.

Answer 2

In electric field charge will experience a force which is given by

F=qE

q=F/E

q=3.7×10^-2/54

q=0.00068C