Question

Given the equation y − 3 = one half(x + 6) in point-slope form, identify the equation of the same line in standard form.

x − 2y = −12
y = one halfx
y = one halfx + 6
y = one halfx + 9

Answer 1

`x-2y=-12`

Explanation:

We have been given an equation of a line in point-slope form. We are asked to write our given equation in standard form.

`y-3=(1)/(2) (x+6)`

Since we know that standard form of equation is: where, a, b and c are constants.

Let us multiply both sides of our given equation by 2.

`(y-3)*2=2*(1)/(2) (x+6)\\2y-6=x+6`

Let us add 6 to both sides of our equation.

`2y-6+6=x+6+6`

`2y=x+12`

Let us subtract x from both sides of our equation.

`2y-x=x-x+12\\2y-x=12`

Multiply both sides of our equation by -1.

`-2y+x=-12`

Rearranging our equation we will get,

`x-2y=-12`

Therefore, the standard form of our given equation is
`x-2y=-12`

and option A is the correct choice.