Question

A car decelerates from 120km/hr to 75 km/hr in 3 seconds. What is it’s acceleration? How far does it travel during this time?

Answer 1

-4.167m/s, 81.2385m

Step-by-step explanation:

initial velocity=120km/hr = 33.33m/s

final velocity=75km/hr = 20.83 m/s

t=3s

Acceleration=v-u/t

a=(20.83-33.33)/3

a=-12.5/3

a=-4.167

Therefore, the acceleration is -4.167 m/s^2

s=ut+1/2at^2

33.33*3+1/2*-4.167*3^2

81.2385 m