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How many formula units in 91.9g aluminum hydroxide
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How many formula units in 91.9g aluminum hydroxide

User Alberto Monteiro
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Answer:

Mass = 3.75g

Molar mass of Al(OH)3 = 78g/mol

moles = 3.75g/78g/mol = 0.048 moles

3. Mass of 4.86moles of B2O3

mass= moles x molar mass

Molar mass of B2O3 = 69.63g/mol

mass= 4.86moles x 69.63g/moles = 338.40g

Step-by-step explanation:

I hope help this answer

User StardustGogeta
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