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1. What is the acceleration of the object between times t = 0 and t = 2

?
2. What is the acceleration of the object between times t = 10 and
t = 12?
3. What is the net displacement of the object between times t = 0 and
t = 16?

User Zerbene
by
3.4k points

1 Answer

7 votes

Answer:

4m/s²

-2m/s²

100m

Step-by-step explanation:

1. What is the acceleration of the object between times t=0s and t= 2s = ( 8 - 0)/(2 - 0)

= 8/2

= 4 m/s²

2. What is the acceleration of the object between times t=10s and t= 12s = ( 4 - 8)/(12 - 10)

= -4/2

= -2 m/s²

3. What is the net displacement of the object between times t=0s and t=16s.​

= (1/2)(0+8)(2-0)+8(10-2)+(1/2)(8+4)(12-10)+4(16 - 12)

= 8 + 64 + 12 + 16

= 100 m

I hope this helps :) I also hope I used the same values as you have lol.

User Kenberkeley
by
4.0k points