Question

In the figure diameter DE is drawn with the midpoint of the circle at C(-3; 2).

EA is a tangent to the circle at E (1,3).

Answer 1

4

Explanation:

`gradient = (y2 - y1)/(x2 - x1)`

`y2 = - 3 \\ y1 = 3 \\ x2 = 2 \\ x1 = 3`

`( - 3 - 1)/(2 - 3) = ( - 4)/( - 1) = 4`