In the figure diameter DE is drawn with the midpoint of the circle at C(-3; 2). EA is a tangent to the circle at E (1,3).

asked Mar 25, 2023 152k views

24 votes

In the figure diameter DE is drawn with the midpoint of the circle at C(-3; 2).

EA is a tangent to the circle at E (1,3).

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5 votes

Answer:

Explanation:

gradient = (y2 - y1)/(x2 - x1)

$y2 = - 3 \\ y1 = 3 \\ x2 = 2 \\ x1 = 3$

( - 3 - 1)/(2 - 3) = ( - 4)/( - 1) = 4

HMHero answered Mar 30, 2023

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