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11. A dog sits 2.50m from the center of a merry-go-round and revolves at a tangential speed of 1.50m/s. If the dog's mass iş 19.5 kg. What is the magnitude of the centripetal force on the dog? (Fc=myt/r)
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11. A dog sits 2.50m from the center of a merry-go-round and revolves at a tangential

speed of 1.50m/s. If the dog's mass iş 19.5 kg. What is the magnitude of the
centripetal force on the dog? (Fc=myt/r) (show all the work]

User Ashwin Singh
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1 Answer

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Fc=mv2/r formula of centripetal force will be applied here with radius mass and velocity described in the above question
User Mohini Mhetre
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6.6k points
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