Question

Suppose a free-fall ride at an amusement park starts at rest and Is In free fall.

a. What is the velocity of the ride after 2.3 s?
m/s
b. How far do people on the ride fall during the 2.3-s time period?
m

Answer 1

Answer: 22.54 m/s and 25.921 meters

Step-by-step explanation:

hey dog have you ever heard of these cool equations..

`v=v_(o) + at`

dude what DOES THIS MEAN??? ok ill tell you. velocity equals initial velocity plus acceleration times time. uhh... interesting.... hmm...

lets do some substitution...

we know that a means acceleration and gravity is a type of acceleration. ok?

`v = 0 + (9.8)(2.3)`

remember I PUT THE ZERO THERE BECAUSE IT STARTED AT REST

22.54 is the velocity

now for b. look at THIS COOL NEW EQUATION

`delta Y = (1)/(2)at^(2) + v_(o)t`

ok so i put delta Y but it can also be delta X it just means displacement... i put delta Y because these kids are falling straight down in a rollercoaster like space mountain or something... ok lets do some replacing am i right?...

`(1)/(2)(9.8)(2.3^(2)) + 0(2.3)`

LISTEN! forget about the zero times 2.3 its just gonna be zero anyways.

so lets calculate... and we get 25.921 meters (or if you want to round to 2 sig figs then its 26 meters)

have a swag day