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The sum of three times a number n and 8 is no more than 25

2 Answers

4 votes

Answer:
(17)/(3)


\quad \begin{bmatrix}\mathrm{Solution:}\:&amp;\:n<(17)/(3)\:\\ \:\mathrm{Decimal:}&amp;\:n<5.66666\dots \\ \:\mathrm{Interval\:Notation:}&amp;\:\left(-\infty \:,\:(17)/(3)\right)\end{bmatrix}

Explanation:

The question is an Algebra type of question. Before I learned Algebra, I usually just did as the question asked, I thought about what it meant. However, we can easily find the number "n" by following it in Algebraic terms.

Step 1: Set up an equation

  • Pick out the values

"the sum of three times a number n and 8 is no more than 25"

Three times a number, "n"


3n

The sum means addition, so;


3n\:+

And 8. Combine;


3n+8

No more than 25, which means that both of them combined would still not result in something greater than 25, so it is less than 25.


3n+8<25

The Equation to solving the problem is
3n+8<25. Now we just have to solve it.

Step 2: Solve the equation

  • Subtract 8 from both sides


3n+8<25\\:\:\:\:\:-8\:\:\:-8

Plus 8 minus 8 cancels out. So we are left with 25-8 = 17.


3n<17

  • Divide both sides by 3


(3n)/(3)<(17)/(3)\\\\n<(17)/(3)

User Brian Kung
by
6.2k points
6 votes

Answer:

n = 17/3

or

(infinity, 17/3]

Explanation:

3n + 8 < 25

-8 < -8

3n < 17

3n/3 < 17/3

No more than would actually be less than or equal to. because the sum has to be under 25.

User Indhu Bharathi
by
6.3k points
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