Register
How many grams are in 9.05 x 1023 atoms of silicon?
12.0k views
3 votes
How many grams are in 9.05 x 1023 atoms of silicon?

User Hornbake
by
5.1k points

1 Answer

6 votes

Step-by-step explanation:

Number of moles(n)=Number of atoms(N)/Avogadro's constant.

Avogadro's constant=6.02×10²³

so we have

n=9.05×10²³/6.02×10²³

n=1.0503moles.

n=mass/molar mass

1.0503=mass/28

mass=1.0503×28

mass=29.4084g

User Decades
by
4.8k points
Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

5.1m questions

6.7m answers

Other Questions

What's the formula for the combined gas law?
Which option describes nonmetals?
The ions Ca2+ and PO43- form salt with the formula
Carnot Cycle. If a boiler's heat source produces 106 Btu/hr at 600F, what is the highest possible rate at which work may be produced? The ambient air is 70F.
HELP, I NEED TO CHECK MY ANSWERS!! what is the mass for a... paperclip, red book, block, pencil, calculator, green blob, penny, quarter, dime, and a nickel?
Link Copied!