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\begin{aligned} \dfrac43&=q+\dfrac13\\\\ \dfrac43-\dfrac13&=q+\dfrac13-\dfrac13&\green{\text{Step } 1}\\\\ \dfrac23&=q&\blue{\text{Step } 2} \end{aligned}

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=q+
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=q+
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=q

User Parzifal
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1 Answer

6 votes

Answer:

interesting question lemme think first

User Mbigras
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