Question

The bowling scores for six people are 112, 114, 115, 120, 122, 290. What si the most appropriate measure of Center?

Answer 1

We need mean .

Let's use python .

Program attached

• Mean=145.5

Answer 2

`{ \rm{mean = ( \sum(fn))/(n) }} \\`

• substitute and solve:

`{ \rm{mean = (112 + 114 + 115 + 120 + 122 + 290)/(6) }} \\ \\ { \rm{mean = (873)/(6) }} \\ \\ { \boxed{ \rm{ \: center = 145.5 \: }}}`