How do you solve for (w-2)²-63=0 where w is a real number

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asked May 18, 2022 123k views

1 Answer

Pong Petrung · Answer 1 · 2022-05-24T16:08:50+0000

(w-2)^2 = 63

FOIL left hand side:
(w-2)^2 = w^2 - 4w + 4

So,
w^2 - 4w + 4 = 63
w^2 - 4w - 59 = 0

Then use quadratic equation to get values of w = 2 + 3*root(7) and w = 2 - 3*root(7).
±
3
√
7

How do you solve for (w-2)²-63=0 where w is a real number

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