Question

60 points! please help me! will appreciate it!

Answer 1

`\huge\boxed{\sf 49.41\ L}`

Step-by-step explanation:

In the reaction:

for every 3 moles of H₂, 2 moles of NH₃ are produced.

Converting 25 g of Ammonia into moles:

Moles = mass / molar mass

= 25 / (14 + 1 × 3)

= 25 / (14 + 3)

= 25 / 17

= 1.47 mol

From the reaction:

2 NH₃ = 3 H₂

1 NH₃ = 3/2 H₂

1 NH₃ = 1.5 H₂

1.47 mol of NH₃ = 1.5 × 1.47 mol of H₂

1.47 mol of NH₃ = 2.2 mol of H₂

So, 2.2 mol of H₂ are needed to produce 1.47 mol (25 g) of NH₃

Converting 2.2 mol of H₂ into L:

= mole × molar value

[molar value = 22.4 L/mol]

= 2.2 × 22.4

= 49.41 L

`\rule[224]{225}{2}`