Question

5. A gas at 2.0 atm and 25 C has an initial volume of 1.00 L. The pressure of the gas increases to 12.0 atm and the temperature is raised to 125 C. What is the new volume of the gas?

Answer 1

V2 = 0.223 L

Step-by-step explanation:

T1 = 25C = 298.15 K

P1 = 2.0 atm

V1 = 1.00 L

T2 = 125C = 398.15 K

P2 = 12.0 atm

V2 = ?

P1V1/T1 = P2V2/T2 must be changed to T2P1V1/T1/P2

398.15 x 2.0 x 1.00 ÷ 298.15 ÷ 12.0 = V2

V2 = 0.223 L

So 0.223 L is the answer!!