Question

A scuba diver descends in the water at a rate of 20 1/2 feet per minute for 2.8 minutes. He immediately changes course when he sees a large fish and ascends at a rate of 25 feet per minute for 2 minutes. What is the scuba diver's position relative to sea level after the 4.8 minutes?

Answer 1

I tried to but they picture on but it did not work for some reason but the answer is -7.4

Explanation:

Answer 2

• 7.4 feet below sea level

Explanation:

Assumed the starting point is the sea level 0.

After 2.8 min the diver is at position:

• 20 1/2 * 2.8 =
• 20.5 * 2.8 =
• 57.4 feet below sea level

The position change after next 2 minutes:

• 25*2 = 50 feet

The position of the diver after 4.8 min:

• 57.4 - 50 = 7.4 feet below sea level