Question

Pls hurry, I need help! Solve the following question by factoring:

Answer 1

`\huge\boxed{\bf\:x = -(4)/(3)}`

Explanation:

`9x ^ { 2 } +24x+20=4`

Bring 4 to the left hand side of the equation .

`9x^(2)+24x+20-4=0`

Subtract 4 from 20.

`9x^(2)+24x+16=0`

Now, factorise it using the splitting-the-middle-term method .

`9x^(2)+24x+16=0 \\9x^(2)+12x+12x+16 =0\\\left(9x^(2)+12x\right)+\left(12x+16\right)=0 \\3x\left(3x+4\right)+4\left(3x+4\right) =0\\\left(3x+4\right)\left(3x+4\right) = 0\\\left(3x+4\right)^(2) = 0`

Now since both the factors are the same, take one of them,

`3x + 4 = 0\\3x = - 4\\\boxed{\bf\:x = -(4)/(3)}`

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Answer 2

• 9x²+24x+20=4
• (3x)²+2(3x)(4)+20-4=4-4
• (3x)²+2(3x)(4)+16=0
• (3x)²+2(3x)(4)+4²=0
• (3x+4)²=0
• 3x+4=0
• x=-4/3