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State the equation of the line described.

A line passes through the point (-3,7) and is perpendicular to the line y = -9x + -1.


thanks for your help!

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Answer:

Explanation:

Perpendicular lines have negative reciprocal slopes. This means that when you multiply the slopes of the perpendicular lines, its product = -1.

Given the linear equation, y = -9x - 1, and the point, (-3, 7):

Since the slope of the given linear equation is: m1 = -9, then it means that the slope of the other line (m2) = 1/9:

m1 × m2 = -1

-9 × 1/9 = -1

Next, we need to find the y-intercept of the other line. The y-intercept is the point on the line where it crosses the y-axis, and has coordinates (0, b). It is also the value of the y-coordinate when its corresponding x-coordinate = 0.

Using the given point, (-3, 7), and the slope of the other line, m2 = 1/9:

We need to substitute these values into the slope-intercept form, y = mx + b, to solve for the y-intercept, (b):

y = mx + b

7 = 1/9(-3) + b

7 = -1/3 + b

Add 1/3 to both sides of the equation to solve for b:

7 + 1/3 = 1/3 -1/3 + b

22/3 = b

Therefore, the y-intercept (b) = 22/3.

The linear equation of the other line is: y = 1/9x + 22/3

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