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Find 8th and 10th of G.P whose first term and common ratio are 6 and 2 respectively​

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Answer:

a₈ = 768 , a₁₀ = 3072

Explanation:

The nth term of a GP is


a_(n) = a₁
(r)^(n-1)

where a₁ is the first term and r the common ratio

Here a₁ = 6 and r = 2 , then

a₈ = 6 ×
2^(7) = 6 × 128 = 768

a₁₀ = 6 ×
2^(9) = 6 × 512 = 3072

User Makiko
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